UGC NET JRF Selection Process 2019 – Complete Guide
UGC NET JRF selection process 2019 is one of the main features to be optimized before applying for the exam. Selection procedure makes you aware of the stages of the selection in that particular exam. Especially when it comes to UGC NET Exam, you need to be aware of every aspect of the UGC NET Selection Process. To give you a brief today, we are sharing the complete UGC NET JRF selection procedure 2019 which will be based on the two tests – Paper I & Paper II to help you for NET exam preparation.
Just to brief you, UGC NET Selection Criteria consists of two examinations, i.e., Paper 1 and 2. UGC NET Selection Process is one of the toughest Selection processes since a very low percentage of total candidates clear the UGC ENT JRF Selection Examination.
UGC NET JRF 2019 notification has been released on 1st March 2019. Candidates those who are eligible for UGC NET JRF 2019 exam should go through the complete details about 2019 UGC NET JRF Selection Process.
UGC NET JRF 2019 Selection Procedure stages
UGC NET Selection Criteria is based on 2 major aspects. Those are given below:
- Paper – I
- Paper – II
UGC NET JRF 2019 – Paper – I
There are different levels for the NET JRF Selection Procedure. Paper 1 of NET JRF exam is an objective Written Examination. It is a one-hour examination, having 50 Questions. The Paper 1 exam of UGC NET will be held in the month of June 2019. For each right answer, a student gets +2 mark and for each incorrect answer, no negative score is given. So all the students are recommended to attempt all the questions. The score obtained in Paper – I examination is considered in the final score as well. An applicant should secure maximum marks in Paper I to lighten the burden. You can select the date of examination in the given time period. Both papers take place on the same day. The design of question paper 1 is as follows:
Exam Duration: 60 minutes
|People & Environment||5||10|
The Qualifying marks for Paper 1 General C
UGC NET JRF 2019 – Paper II
Paper II exam is the Second stage under the UGC NET JRF Selection Procedure. UGC NET JRF 2019 will be held on the same date as of Paper I.Paper I and Paper II will be held on the same day in a span of three hours. Paper II exam holds an important role in the UGC NET JRF Selection Procedure. The Overall Selection is based on the marks obtained by a candidate in both the exams, so it is very important for a student to score equally good marks in both the exams as just cracking the cut off will not help you to achieve a certificate of UGC NET JRF.
This stage depends on the subject you want to get your certification in. It contains 100 questions. The syllabus of Paper II is the complete syllabus of Graduation & Post Graduation of that particular subject. For each right answer, a student gets +2 mark and for each incorrect answer, no negative score is given. So all the students are recommended to attempt all the questions. The score obtained in Paper – II examination is considered in the final score as well.
Total Exam Duration: 180 minutes.
Note: Paper I and Paper II will be set in both language English and Hindi. A candidate who is giving the exam has to secure minimum marks independently in each paper and total also.
Some Important Points to ponder:
1) Each Candidate has to qualify in each of the tests as per the marks prescribed by the NTA (National Testing Agency).
2) Never forget to attempt all the questions as there is no negative marking.
3) Candidate will be selected on the basis of the marks obtained in Paper I exam & Paper II Exam.
4) So, it is very important for a student to not secure the cut off marks but also score enough marks to make it to the merit list.
For more practice and better chances to Crack
NTA NET JRF Courses
- Research Aptitude
- Teaching Aptitude
- Higher Education
- Complete Paper 1